C Program to display arithmetic operator using switch case

#include

void main()

{

 int d;

 float a,b;

 printf("1-Addition\n2-Subtraction\n3-Multlipication\n4-Division\n");

 printf("Enter choice\n");

 scanf("%d",&d);

 if(d>0&&d<5 font="">

  {

   switch(d)

    {

     case 1: printf("enter 1st no.\n");

             scanf("%f",&a);

             printf("enter 2nd no.\n");

             scanf("%f",&b);

             printf("Sum is %f\n",a+b);

             break;

     case 2: printf("enter 1st no.\n");

             scanf("%f",&a);

             printf("enter 2nd no.\n");

             scanf("%f",&b);

             printf("difference is %f\n",a-b);

             break;

     case 3: printf("enter 1st no.\n");

             scanf("%f",&a);

             printf("enter 2nd no.\n");

             scanf("%f",&b);

             printf("Multlipication is %f\n",a*b);

             break;

     case 4: printf("enter dividened\n");

             scanf("%f",&a);

             printf("enter divisor\n");        

             scanf("%f",&b);

             printf("Division is %f\n",a/b);

             break;                

    }

  }

 else

 printf("Wrong choice entered\n");

}

Output: